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11TH · MATH

Question 1

menu_bookSolutionmenu_bookTheorymenu_book•(i)f(x)=x2+6x+13f(x)=x^2+6x+13f(x)=x2+6x+13menu_book•(ii)f(x)=x2+4xf(x)=x^2+4xf(x)=x2+4xmenu_book•(iii)f(x)=−x2+8x+13f(x)=-x^2+8x+13f(x)=−x2+8x+13menu_book•(iv)f(x)=−x2−3x−5f(x)=-x^2-3x-5f(x)=−x2−3x−5menu_book•(v)f(x)=3x2+6x−13f(x)=3x^2+6x-13f(x)=3x2+6x−13menu_book•(vi)f(x)=−2x2−x+21f(x)=-2x^2-x+21f(x)=−2x2−x+21
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school

11TH · MATH

Question 1

menu_bookSolutionmenu_bookTheorymenu_book•(i)f(x)=x2+6x+13f(x)=x^2+6x+13f(x)=x2+6x+13menu_book•(ii)f(x)=x2+4xf(x)=x^2+4xf(x)=x2+4xmenu_book•(iii)f(x)=−x2+8x+13f(x)=-x^2+8x+13f(x)=−x2+8x+13menu_book•(iv)f(x)=−x2−3x−5f(x)=-x^2-3x-5f(x)=−x2−3x−5menu_book•(v)f(x)=3x2+6x−13f(x)=3x^2+6x-13f(x)=3x2+6x−13menu_book•(vi)f(x)=−2x2−x+21f(x)=-2x^2-x+21f(x)=−2x2−x+21
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Accedmychevron_right11thchevron_rightmathchevron_rightTheory Of Quadratic Functionschevron_rightExercise 3.1

(iv)

max⁡f(x)=−114 at x=−32\boxed{\max f(x)=-\frac{11}{4}\text{ at }x=-\frac{3}{2}}maxf(x)=−411​ at x=−23​​
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