Accedmychevron_right11thchevron_rightmathchevron_rightComplex Numberschevron_rightExercise 1.1

(iv) (z1+z2)3|(z_1+z_2)^3|

Solution

First find z1+z2:z1+z2=(2+7i)+(5+3i)=3+10iUse property zn=zn:(z1+z2)3=z1+z23z1+z2=3+10i=(3)2+102=109(z1+z2)3=(109)3=109109\begin{aligned} & \boxed{\text{First find } z_1+z_2:} \\ \\ & z_1+z_2=(2+7i)+(-5+3i)=-3+10i \\ \\ & \boxed{\text{Use property } |z^n|=|z|^n:} \\ \\ & |(z_1+z_2)^3|=|z_1+z_2|^3 \\ \\ & |z_1+z_2|=|-3+10i|=\sqrt{(-3)^2+10^2}=\sqrt{109} \\ \\ & |(z_1+z_2)^3|=(\sqrt{109})^3=109\sqrt{109} \end{aligned}