Accedmychevron_right11thchevron_rightmathchevron_rightComplex Numberschevron_rightExercise 1.1

Solution

Given z1=2+7i, z2=5+3i.\boxed{\text{Given } z_1=2+7i,\ z_2=-5+3i.}

(i) 2z14z2|2z_1-4z_2|

2z1=2(2+7i)=4+14i4z2=4(5+3i)=20+12i2z14z2=(4+14i)(20+12i)=24+2i2z14z2=24+2i=242+22=576+4=580=2145\begin{aligned} & \boxed{2z_1=2(2+7i)=4+14i} \\ \\ & \boxed{4z_2=4(-5+3i)=-20+12i} \\ \\ & 2z_1-4z_2=(4+14i)-(-20+12i) \\ & = 24+2i \\ \\ & |2z_1-4z_2| = |24+2i| = \sqrt{24^2+2^2} \\ & = \sqrt{576+4}=\sqrt{580}=2\sqrt{145} \end{aligned}

(ii) 3z1+2z2|3z_1+2z_2|

3z1=3(2+7i)=6+21i2z2=2(5+3i)=10+6i3z1+2z2=(6+21i)+(10+6i)=4+27i3z1+2z2=4+27i=(4)2+272=16+729=745\begin{aligned} & \boxed{3z_1=3(2+7i)=6+21i} \\ \\ & \boxed{2z_2=2(-5+3i)=-10+6i} \\ \\ & 3z_1+2z_2=(6+21i)+(-10+6i) \\ & = -4+27i \\ \\ & |3z_1+2z_2| = |-4+27i| = \sqrt{(-4)^2+27^2} \\ & = \sqrt{16+729}=\sqrt{745} \end{aligned}

(iii) 7z2+2z2ˉ|-7z_2+2\bar{z_2}|

z2=5+3i  z2ˉ=53i7z2=7(5+3i)=3521i2z2ˉ=2(53i)=106i7z2+2z2ˉ=(3521i)+(106i)=2527i7z2+2z2ˉ=2527i=252+(27)2=625+729=1354\begin{aligned} & \boxed{z_2=-5+3i\ \Rightarrow\ \bar{z_2}=-5-3i} \\ \\ & -7z_2=-7(-5+3i)=35-21i \\ & 2\bar{z_2}=2(-5-3i)=-10-6i \\ \\ & -7z_2+2\bar{z_2}=(35-21i)+(-10-6i) \\ & = 25-27i \\ \\ & |-7z_2+2\bar{z_2}| = |25-27i| = \sqrt{25^2+(-27)^2} \\ & = \sqrt{625+729}=\sqrt{1354} \end{aligned}

(iv) (z1+z2)3|(z_1+z_2)^3|

z1+z2=(2+7i)+(5+3i)=3+10i(z1+z2)3=z1+z23z1+z2=3+10i=(3)2+102=109(z1+z2)3=(109)3=109109\begin{aligned} & z_1+z_2=(2+7i)+(-5+3i)=-3+10i \\ \\ & \boxed{|(z_1+z_2)^3|=|z_1+z_2|^3} \\ \\ & |z_1+z_2|=|-3+10i|=\sqrt{(-3)^2+10^2}=\sqrt{109} \\ \\ & |(z_1+z_2)^3|=(\sqrt{109})^3=109\sqrt{109} \end{aligned}