QuestionsQuestion 1Express the following products as sums or differences:(i)2sin3θcosθ2\sin 3\theta \cos\theta2sin3θcosθ(ii)2cos5θsin3θ2\cos 5\theta \sin 3\theta2cos5θsin3θ(iii)sin5θcos2θ\sin 5\theta \cos 2\thetasin5θcos2θ(iv)2sin7θsin2θ2\sin 7\theta \sin 2\theta2sin7θsin2θ(v)cos(x+y)sin(x−y)\cos(x+y)\sin(x-y)cos(x+y)sin(x−y)(vi)cos(2x+30∘)cos(2x−30∘)\cos(2x+30^\circ)\cos(2x-30^\circ)cos(2x+30∘)cos(2x−30∘)(vii)sin12∘sin46∘\sin 12^\circ \sin 46^\circsin12∘sin46∘(viii)sin(x+45∘)sin(x−45∘)\sin(x+45^\circ)\sin(x-45^\circ)sin(x+45∘)sin(x−45∘)SolutionTheoryQuestion 2Express the following sums or differences as products:(i)sin5θ+sin3θ\sin 5\theta + \sin 3\thetasin5θ+sin3θ(ii)sin8θ−sin4θ\sin 8\theta - \sin 4\thetasin8θ−sin4θ(iii)cos6θ+cos3θ\cos 6\theta + \cos 3\thetacos6θ+cos3θ(iv)cos7θ−cosθ\cos 7\theta - \cos\thetacos7θ−cosθ(v)cos12∘+cos48∘\cos 12^\circ + \cos 48^\circcos12∘+cos48∘(vi)sin(x+30∘)+sin(x−30∘)\sin(x+30^\circ) + \sin(x-30^\circ)sin(x+30∘)+sin(x−30∘)SolutionTheoryQuestion 3Prove the following identities:(i)sin3x−sinxcosx−cos3x=cot2x\dfrac{\sin 3x - \sin x}{\cos x - \cos 3x} = \cot 2xcosx−cos3xsin3x−sinx=cot2x(ii)sin8x+sin2xcos8x+cos2x=tan5x\dfrac{\sin 8x + \sin 2x}{\cos 8x + \cos 2x} = \tan 5xcos8x+cos2xsin8x+sin2x=tan5x(iii)sinA−sinBsinA+sinB=tanA−B2cotA+B2\dfrac{\sin A - \sin B}{\sin A + \sin B} = \tan\dfrac{A-B}{2}\cot\dfrac{A+B}{2}sinA+sinBsinA−sinB=tan2A−Bcot2A+B(iv)sin80∘+sin40∘cos80∘+cos40∘=3\dfrac{\sin 80^\circ + \sin 40^\circ}{\cos 80^\circ + \cos 40^\circ} = \sqrt{3}cos80∘+cos40∘sin80∘+sin40∘=3SolutionTheoryQuestion 4Prove that:(i)cos15∘+cos105∘+cos195∘+cos160∘+cos285∘=0\cos 15^\circ + \cos 105^\circ + \cos 195^\circ + \cos 160^\circ + \cos 285^\circ = 0cos15∘+cos105∘+cos195∘+cos160∘+cos285∘=0(ii)sin2θ+sin4θ+sin6θ+sin8θcos2θ+cos4θ+cos6θ+cos8θ=tan5θ\dfrac{\sin 2\theta + \sin 4\theta + \sin 6\theta + \sin 8\theta}{\cos 2\theta + \cos 4\theta + \cos 6\theta + \cos 8\theta} = \tan 5\thetacos2θ+cos4θ+cos6θ+cos8θsin2θ+sin4θ+sin6θ+sin8θ=tan5θSolutionTheoryQuestion 5Prove that:(i)cos20∘cos40∘cos60∘cos80∘=116\cos 20^\circ \cos 40^\circ \cos 60^\circ \cos 80^\circ = \dfrac{1}{16}cos20∘cos40∘cos60∘cos80∘=161(ii)sinπ9sin2π9sinπ3sin4π9=316\sin\dfrac{\pi}{9}\sin\dfrac{2\pi}{9}\sin\dfrac{\pi}{3}\sin\dfrac{4\pi}{9} = \dfrac{3}{16}sin9πsin92πsin3πsin94π=163(iii)sin10∘sin30∘sin50∘sin70∘=116\sin 10^\circ \sin 30^\circ \sin 50^\circ \sin 70^\circ = \dfrac{1}{16}sin10∘sin30∘sin50∘sin70∘=161SolutionTheoryQuestion 6Prove that: sin3θ1+2cos2θ=sinθ\dfrac{\sin 3\theta}{1 + 2\cos 2\theta} = \sin\theta1+2cos2θsin3θ=sinθ; deduce the value of sin15∘\sin 15^\circsin15∘.SolutionTheoryQuestion 7Prove that: tan75∘−tan15∘=23\tan 75^\circ - \tan 15^\circ = 2\sqrt{3}tan75∘−tan15∘=23.SolutionTheoryQuestion 8Prove that: cos15∘−sin15∘=12\cos 15^\circ - \sin 15^\circ = \dfrac{1}{\sqrt{2}}cos15∘−sin15∘=21.SolutionTheoryQuestion 9Prove that: sin2α−sin2βsinαcosα−sinβcosβ=tan(α+β)\dfrac{\sin^2\alpha - \sin^2\beta}{\sin\alpha \cos\alpha - \sin\beta \cos\beta} = \tan(\alpha + \beta)sinαcosα−sinβcosβsin2α−sin2β=tan(α+β).SolutionTheoryQuestion 10Prove that: sinα+sinβ+sinγ−sin(α+β+γ)=4sinα+β2sinβ+γ2sinγ+α2\sin\alpha + \sin\beta + \sin\gamma - \sin(\alpha + \beta + \gamma) = 4\sin\dfrac{\alpha + \beta}{2}\sin\dfrac{\beta + \gamma}{2}\sin\dfrac{\gamma + \alpha}{2}sinα+sinβ+sinγ−sin(α+β+γ)=4sin2α+βsin2β+γsin2γ+α.SolutionTheory