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11TH · MATH

Question 2

menu_bookSolutionmenu_bookTheorymenu_book•(i)sin⁡(45∘+α)=12(sin⁡α+cos⁡α)\sin(45^\circ + \alpha) = \dfrac{1}{\sqrt{2}}(\sin\alpha + \cos\alpha)sin(45∘+α)=2​1​(sinα+cosα)menu_book•(ii)cos⁡(α+45∘)=12(cos⁡α−sin⁡α)\cos(\alpha + 45^\circ) = \dfrac{1}{\sqrt{2}}(\cos\alpha - \sin\alpha)cos(α+45∘)=2​1​(cosα−sinα)
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school

11TH · MATH

Question 2

menu_bookSolutionmenu_bookTheorymenu_book•(i)sin⁡(45∘+α)=12(sin⁡α+cos⁡α)\sin(45^\circ + \alpha) = \dfrac{1}{\sqrt{2}}(\sin\alpha + \cos\alpha)sin(45∘+α)=2​1​(sinα+cosα)menu_book•(ii)cos⁡(α+45∘)=12(cos⁡α−sin⁡α)\cos(\alpha + 45^\circ) = \dfrac{1}{\sqrt{2}}(\cos\alpha - \sin\alpha)cos(α+45∘)=2​1​(cosα−sinα)
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