Accedmychevron_right11thchevron_rightmathchevron_rightSequences And Serieschevron_rightExercise 6.9

Equation (a(b-c)x^2+b(c-a)x+c(a-b)=0) has equal roots.

Discriminant = 0: [ [b(c-a)]^2-4\cdot a(b-c)\cdot c(a-b)=0 ]

Expanding and simplifying yields (2/b=1/a+1/c), i.e. (a,b,c) in H.P.

Proved.