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11TH · MATH

Question 16

menu_bookSolutionmenu_bookTheorymenu_book•(i)a−bb−c=ac\dfrac{a-b}{b-c} = \dfrac{a}{c}b−ca−b​=ca​menu_book•(ii)(a−c)2=(a+c)(a−2b+c)(a-c)^2 = (a+c)(a-2b+c)(a−c)2=(a+c)(a−2b+c)
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11TH · MATH

Question 16

menu_bookSolutionmenu_bookTheorymenu_book•(i)a−bb−c=ac\dfrac{a-b}{b-c} = \dfrac{a}{c}b−ca−b​=ca​menu_book•(ii)(a−c)2=(a+c)(a−2b+c)(a-c)^2 = (a+c)(a-2b+c)(a−c)2=(a+c)(a−2b+c)
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