schoolAccedmy
9th10th
11th12th
school

11TH · MATH

Question 3

menu_bookSolutionmenu_bookTheorymenu_book•(i)nPr=n⋅n−1Pr−1{}^nP_r = n \cdot {}^{n-1}P_{r-1}nPr​=n⋅n−1Pr−1​menu_book•(ii)nPr=n−1Pr+r⋅n−1Pr−1{}^nP_r = {}^{n-1}P_r + r \cdot {}^{n-1}P_{r-1}nPr​=n−1Pr​+r⋅n−1Pr−1​
arrow_backBack
school

11TH · MATH

Question 3

menu_bookSolutionmenu_bookTheorymenu_book•(i)nPr=n⋅n−1Pr−1{}^nP_r = n \cdot {}^{n-1}P_{r-1}nPr​=n⋅n−1Pr−1​menu_book•(ii)nPr=n−1Pr+r⋅n−1Pr−1{}^nP_r = {}^{n-1}P_r + r \cdot {}^{n-1}P_{r-1}nPr​=n−1Pr​+r⋅n−1Pr−1​
arrow_backBack
Accedmychevron_right11thchevron_rightmathchevron_rightPermutations And Combinationschevron_rightExercise 7.2

Proved

Next Part
(ii)
arrow_forward
On this page
No headings yet