QuestionsQuestion 1Evaluate each of the following:(i)10!0! 8!\dfrac{10!}{0!\,8!}0!8!10!(ii)12!3!(12−3)!\dfrac{12!}{3!(12-3)!}3!(12−3)!12!(iii)14403! 4!+24005! 2!\dfrac{1440}{3!\,4!} + \dfrac{2400}{5!\,2!}3!4!1440+5!2!2400(iv)(n+2)!(n+1)!\dfrac{(n+2)!}{(n+1)!}(n+1)!(n+2)!SolutionTheoryQuestion 2Write each of the following in the factorial form:(i)n3−nn^3 - nn3−n(ii)n(n−1)(n−2)⋯(n−r+1)n(n-1)(n-2)\cdots(n-r+1)n(n−1)(n−2)⋯(n−r+1)SolutionTheoryQuestion 3Find nnn, if (n+4)!=3024⋅n!(n+4)! = 3024 \cdot n!(n+4)!=3024⋅n!.SolutionTheoryQuestion 4If 17!+18!=x9!\dfrac{1}{7!} + \dfrac{1}{8!} = \dfrac{x}{9!}7!1+8!1=9!x, find xxx.SolutionTheoryQuestion 5Prove that: (2n+1)!n!=[1⋅3⋅5⋯(2n−1)(2n+1)]2n\dfrac{(2n+1)!}{n!} = [1\cdot 3\cdot 5\cdots(2n-1)(2n+1)]2^nn!(2n+1)!=[1⋅3⋅5⋯(2n−1)(2n+1)]2n.SolutionTheoryQuestion 6Express as a single fraction: (n+2)!(r+2)!+(n+1)!(r+1)!\dfrac{(n+2)!}{(r+2)!} + \dfrac{(n+1)!}{(r+1)!}(r+2)!(n+2)!+(r+1)!(n+1)!.SolutionTheoryQuestion 7There are four distinct colored balls and four boxes of same colors as those of the balls. Determine the number of possible ways the balls, one each in a box, can be placed such that a ball does not go to a box of its own colour.SolutionTheory