Solution Let: x+1(x−1)2=Ax−1+B(x−1)2\frac{x+1}{(x-1)^2}=\frac{A}{x-1}+\frac{B}{(x-1)^2}(x−1)2x+1=x−1A+(x−1)2B Multiply by (x−1)2(x-1)^2(x−1)2: x+1=A(x−1)+Bx+1=A(x-1)+Bx+1=A(x−1)+B Put x=1x=1x=1: 2=B2=B2=B Compare coefficients of xxx: 1=A1=A1=A Hence: x+1(x−1)2=1x−1+2(x−1)2\boxed{\frac{x+1}{(x-1)^2}=\frac{1}{x-1}+\frac{2}{(x-1)^2}}(x−1)2x+1=x−11+(x−1)22