Accedmychevron_right11thchevron_rightmathchevron_rightMatrices And Determinantschevron_rightExercise 4.3

Solution

Given scaling matrix:

P=[500050005]P=\begin{bmatrix}-5&0&0\\0&-5&0\\0&0&-5\end{bmatrix}

and AA is mapped to A=(30,20,5)A'=(30,20,-5).

Using the hint:

PA=APA=A'

Let A=(x,y,z)A=(x,y,z). Then:

(5x,5y,5z)=(30,20,5)(-5x,-5y,-5z)=(30,20,-5)

So:

x=6,y=4,z=1x=-6,\quad y=-4,\quad z=1 A=(6,4,1)\boxed{A=(-6,-4,1)}