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11TH · MATH

Question 1

menu_bookSolutionmenu_bookTheorymenu_book•(i)f(x)=2x2+x−5f(x) = 2x^2 + x - 5f(x)=2x2+x−5, $c = 1$menu_book•(ii)f(x)=x2−9x−3f(x) = \dfrac{x^2 - 9}{x - 3}f(x)=x−3x2−9​, $c = -3$menu_book•(iii)f(x)=∣x−5∣f(x) = |x - 5|f(x)=∣x−5∣, $c = 5$
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school

11TH · MATH

Question 1

menu_bookSolutionmenu_bookTheorymenu_book•(i)f(x)=2x2+x−5f(x) = 2x^2 + x - 5f(x)=2x2+x−5, $c = 1$menu_book•(ii)f(x)=x2−9x−3f(x) = \dfrac{x^2 - 9}{x - 3}f(x)=x−3x2−9​, $c = -3$menu_book•(iii)f(x)=∣x−5∣f(x) = |x - 5|f(x)=∣x−5∣, $c = 5$
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