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11TH · MATH

Question 1

menu_bookSolution menu_bookTheory menu_book•(i)

a_n = \dfrac{2n+3}{n+1}

menu_book•(ii)

b_n = \dfrac{2n+3}{n^2+1}

menu_book•(iii)

c_n = \dfrac{5n^2}{2n+3}

menu_book•(iv)

d_n = \dfrac{n^2 - 3n + 1}{2n^2 + n + 4}

school

11TH · MATH

Question 1

menu_bookSolution menu_bookTheory menu_book•(i)

a_n = \dfrac{2n+3}{n+1}

menu_book•(ii)

b_n = \dfrac{2n+3}{n^2+1}

menu_book•(iii)

c_n = \dfrac{5n^2}{2n+3}

menu_book•(iv)

d_n = \dfrac{n^2 - 3n + 1}{2n^2 + n + 4}

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