(vii) f(x−2)=2(x−2)+3=2x−4+3=2x−1\begin{aligned} f(x-2)&=\sqrt{2(x-2)+3}\\ &=\sqrt{2x-4+3}\\ &=\sqrt{2x-1} \end{aligned}f(x−2)=2(x−2)+3=2x−4+3=2x−1 f(x−2)=2x−1\boxed{f(x-2)=\sqrt{2x-1}}f(x−2)=2x−1