QuestionsQuestion 1Find by definition, the derivatives w.r.t. ‘x’ of the following functions defined as:(i)2x2+12x^2 + 12x2+1(ii)2−x2 - \sqrt{x}2−x(iii)1x\dfrac{1}{\sqrt{x}}x1(iv)x(x−3)x(x - 3)x(x−3)SolutionTheoryQuestion 2Find dydx\dfrac{dy}{dx}dxdy from first principle and find gradient of the curve at the given point:(i)x+2\sqrt{x + 2}x+2 at x=6x = 6x=6(ii)1x+a\dfrac{1}{\sqrt{x + a}}x+a1 at x=ax = ax=aSolutionTheoryQuestion 3(i)Find the derivative of x23x^{\frac{2}{3}}x32 at x=8x = 8x=8 from the first principle.(ii)Find the derivative of x2+2x+3x^2 + 2x + 3x2+2x+3 by definition.SolutionTheoryQuestion 4Find from first principle, the derivatives of the following expressions w.r.t. their respective independent variables:(i)(3x−2)−2(3x - 2)^{-2}(3x−2)−2(ii)(2t+3)5(2t + 3)^5(2t+3)5(iii)(aw+b)7(aw + b)^7(aw+b)7SolutionTheoryQuestion 5Find the gradient and equation of the tangent line to y=3x2−4x+1y = 3x^2 - 4x + 1y=3x2−4x+1 at x=2x = 2x=2.SolutionTheoryQuestion 6For the function f(x)=2x3+xf(x) = 2x^3 + xf(x)=2x3+x, calculate the equation of the tangent line at x=−1x = -1x=−1.SolutionTheoryQuestion 7Find the coordinates of the point of tangency and the equation of the tangent line for f(x)=x3−2x+1f(x) = x^3 - 2x + 1f(x)=x3−2x+1 at x=1x = 1x=1.SolutionTheoryQuestion 8Find the gradient of the curve f(x)=3x2+2xf(x) = 3x^2 + 2xf(x)=3x2+2x at x=1x = 1x=1.SolutionTheoryQuestion 9Find the gradient and an equation of tangent line to the graph of f(x)=xf(x) = \sqrt{x}f(x)=x at x=9x = 9x=9.SolutionTheoryQuestion 10The position of a car after ttt hours is given by: s(t)=2t3−3t2+ts(t) = 2t^3 - 3t^2 + ts(t)=2t3−3t2+t (in kilometres)(i)Find the average velocity over the interval [1,4][1, 4][1,4](ii)Find the instantaneous velocity at t=2t = 2t=2SolutionTheoryQuestion 11A stone is thrown upwards and its height after ttt seconds is given by: s(t)=−16t2+32t+10s(t) = -16t^2 + 32t + 10s(t)=−16t2+32t+10 (in feet). Find the instantaneous velocity at t=1t = 1t=1.SolutionTheoryQuestion 12The outdoor temperature (in °C) over time is modeled by: T(t)=−t2+12t+10T(t) = -t^2 + 12t + 10T(t)=−t2+12t+10, where ttt is the time in hours. Find the instantaneous rate of change at t=2t = 2t=2.SolutionTheory