Solution
Use the mapping A=1,…,Z=26.
Word: CODE
C=3, O=15, D=4, E=5
Encryption key:
k=2−i
Encryption (multiply by k)
C:O:D:E: 3(2−i)=6−3i 15(2−i)=30−15i 4(2−i)=8−4i 5(2−i)=10−5i
Encrypted values:
(6−3i, 30−15i, 8−4i, 10−5i)
Decryption (multiply by k−1)
2−i1=(2−i)(2+i)2+i=52+i
Now:
(6−3i)⋅52+i=3,(30−15i)⋅52+i=15,(8−4i)⋅52+i=4,(10−5i)⋅52+i=5
So the decrypted word is CODE.
Encrypted: (6−3i,30−15i,8−4i,10−5i) → Decrypted: CODE