(iv) (5,5π6)(5,\dfrac{5\pi}{6})(5,65π) Here r=5>0r=5>0r=5>0 and θ=5π6\theta=\dfrac{5\pi}{6}θ=65π. x=5cos5π6=−532y=5sin5π6=52\begin{aligned} x&=5\cos\frac{5\pi}{6}=-\frac{5\sqrt{3}}{2}\\ y&=5\sin\frac{5\pi}{6}=\frac{5}{2} \end{aligned}xy=5cos65π=−253=5sin65π=25