Solution Write the complex number in a+ib form:z=1+0i=1Formula for multiplicative inverse:z−1=1a+ib=a−iba2+b2Substitute a=1 and b=0:z−1=1−0i12+02Simplify:=11=1=1+0iWrite in ordered pair form:(1,0)\begin{aligned} & \boxed{\text{Write the complex number in } a+ib \text{ form:}} \\ \\ & z = 1 + 0i = 1 \\ \\ & \boxed{\text{Formula for multiplicative inverse:}} \\ \\ & z^{-1} = \frac{1}{a+ib} = \frac{a-ib}{a^2+b^2} \\ \\ & \boxed{\text{Substitute } a=1 \text{ and } b=0:} \\ \\ & z^{-1} = \frac{1 - 0i}{1^2 + 0^2} \\ \\ & \boxed{\text{Simplify:}} \\ \\ & = \frac{1}{1} = 1 = 1 + 0i \\ \\ & \boxed{\text{Write in ordered pair form:}} \\ \\ & \boxed{(1, 0)} \end{aligned}Write the complex number in a+ib form:z=1+0i=1Formula for multiplicative inverse:z−1=a+ib1=a2+b2a−ibSubstitute a=1 and b=0:z−1=12+021−0iSimplify:=11=1=1+0iWrite in ordered pair form:(1,0)