Case: distinct linear factors If Q(x)=(x−a)(x−b)Q(x)=(x-a)(x-b)Q(x)=(x−a)(x−b) with a≠ba\ne ba=b, then: P(x)(x−a)(x−b)=Ax−a+Bx−b\frac{P(x)}{(x-a)(x-b)}=\frac{A}{x-a}+\frac{B}{x-b}(x−a)(x−b)P(x)=x−aA+x−bB Solve for constants by clearing denominators and substituting convenient xxx values.